Answer:
W=7 and L=11
Step-by-step explanation:
We have two unknowns so we must create two equations.
First the problem states that length of a rectangle is 10 yd less than three times the width so: L= 3w-10
Next we are given the area so: L X W = 77
Then solve for the variable algebraically. It is just a system of equations.
3W^2 - 10W - 77 = 0
(3W + 11)(W - 7) = 0
W = -11/3 and/or W=7
Discard the negative solution as the width of the rectangle cannot be less then 0.
So W=7
Plug that into the first equation.
3(7)-10= 11 so L=11
<h3>F(x) = - 5(x+1+3)</h3>
or, - 12= - 5x-5-15
or, - 12= - 5x-20
or, - 12+20= - 5x
or, 8= - 5x
or, x= 8÷-5
Also,
F(x)= - 5(x+1+3)
or, f(8÷-5)= - 5(8÷-5+1+3)
= - 5(8-5-15÷-5)
= - 5×-12÷-5
= - 12 #
You are enough I know this is not what you expect but just know YOU are enough you are awesome and amazing whatever you are going through just know YOU are enough
