Answer:
yes, becoz all the elements of set R is in set A
Answer:
0.8
Step-by-step explanation:
We can solve P(A or B) by using the following:

Since we know P(A) = 0.6, P(B) = 0.3 and P(A and B) = 0.1 we obtain:

Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.




IQ scores of at least 130.81 are identified with the upper 2%.
<span>2x - 3(-4x + 2 )
2x+12x-6
14x-6
2(7x-3)</span>
Answer:
The question needs more information but you can see that all the numbers in the 1st column are multiplied by 6 to equal the number in column 2
Step-by-step explanation:
3 x6 =18
6 x 6= 36
9 x6= 54
12 x6 =72