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Andrej [43]
2 years ago
9

What is the answer of (-1/4 subtracted by 1/2) divided by (negative 4/7)

Mathematics
1 answer:
Burka [1]2 years ago
7 0
The answer would be 5/8 and 0.625 in decimal form.


1/-4 - 1/2 * 7/-4 (divide then multiply)

1/-4 - 1 * 7 over 2 * -4 (multiply)

1/-4 - 7 over 2 * -4 (simplify 1 * 7 to 7)

1/-4 - 7/-8 (simplify 2 * -4 to -8)

1/-4 - (7/-8) (move the negative sign to the left)

1/-4 + 7/8 (simplify brackets)

5/8 (simplify).

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Which list includes the lower extreme, the lower quartile, the median, the upper quartile, and the upper extreme for the data se
PtichkaEL [24]
Lower extreme- 8
Lower quartile- 20
Median- 30
Upper quartile- 35
Upper extreme- 42

Hope this helps!
7 0
2 years ago
two bicycle riders start from the same point and ride in opposite directions. one rider is moving twice as the other. in 3 hours
Likurg_2 [28]

Step-by-step explanation:

let X = speed of slow bicycle rider

2x=speed of fast bicycle rider

3(x+2x)=72

X=8mph(slowest bicycle rider)

2x=16mph(fastest bicycle rider)

5 0
2 years ago
How would you go about finding the solution to this system of three equations in three variables? Be specific. For example, you
kupik [55]
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6

you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5

II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7

then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15

3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1

insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4

insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2

so the solution is
x=2
y=-4
z=-1
3 0
3 years ago
Name the kind or kinds of symmetry the following figure has: A
denpristay [2]
It is a straight line of symmetry because if you have a paper A and you fold it, it will form a straight line, and that is also meaning a straight line of symmetry. If you fold it any other way, it will not be a line of symmetry.

Hope this helps you ;)
6 0
3 years ago
I need the answers for these please
baherus [9]
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4 0
2 years ago
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