8h/3+19
Move all terms to the left
8-(h/3+19)=0
Get rid of parentheses
-h/3-19+8=0
Multiply all terms by denominator
-h-19*3+8*3=0
Add all numbers and variables together
-1h-33=0
Move all terms containing h to the left all other terms to the right
-h=33
h=33/-1
h=-33
ANSWER
Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
To proof
let us assume that the fluid should be drained and replaced with pure antifreeze be x .
As given
A radiator contains 10 quarts of fluid, 30% of which is antifreeze.
Now write 30% in the decimal form

Now write 60% in the decimal form

After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )
The quantity of antifreeze is

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
than the equation becomes

solyving
100x +300 - 30x = 600
70x = 300

x = 4.28 quarts (approx)
Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
Therefore the option (c.) is correct .
Answer:
x = 180 - (37 + 53)
Step-by-step explanation:
x + 37 + 53 = 180
x = 180 - (37 + 53)
All of the angles have to equal 180 due to the supplementary angles thm
Answer:
when you divide
89736÷40 the answer is 221 with the remainder 16.