Brendan earns 25% more than his regular hourly rate d when he works on holidays. Write an expression to represent the hourly rat
1 answer:
Answer:
The expression that represents hourly rate Brendan earns working on a holiday is .
Step-by-step explanation:
Given:
Regular hourly rate = d
Percent extra Money earned on holidays = 25% more
We need to find expression represent the hourly rate Brendan earns working on a holiday.
Solution:
Extra money earned on holidays can be calculated by Percent extra Money earned on holidays multiplied by Regular hourly rate.
framing in equation form we get;
Extra money earned on holidays =
Now we will find hourly rate Brendan earns working on a holiday.
hourly rate Brendan earns working on a holiday can be calculated by sum of Regular hourly rate plus Extra money earned on holidays.
framing in equation form we get;
hourly rate Brendan earns working on a holiday =
Hence The expression that represents hourly rate Brendan earns working on a holiday is .
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Answer: y - 1 = –(x –7)
or y –5 = –1(x –3)
The attachment shows the graph of these equations (identical)
Step-by-step explanation:
The basic form for a point-slope equation is
y - b = m(x - a)
a is the x-value from the given coordinate, b is the y-value form the given coordinate, m is the slope. x and y are the variables in the function.
To find the slope, m, use the given coordinates. Get the difference in the y-values and divide by the difference in the x-values. This is "rise over run."
Subtract the first coordinate from the second coordinate.
Given coordinate points: (3,5) and (7,1) substitute values:
m= 1 –5 / 7 –3 becomes m= –4/4 so the slope, m = –4/4
That is –1 The "1" is "understood," so only the negative sign represents the slope in the equation
To write the equation: Take the basic form, substitute b and a values from either given coordinate. And use the value of m we just calculated.
y - b = m(x - a) Using the second coordinate: (7,1)
y - 1 = –(x –7)
or using the first coordinate:
y –5 = –(x –3)
The correct answer is the flagpole is <span>33 feet high</span>.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is 33 feet high.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is 33 feet high.