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2 years ago

The sum of three counting number is 72. and the numbers.

Mathematics

2 answers:

Jlenok [28]2 years ago

8 0

Lol it is 23 for real this time

Ira Lisetskai [31]2 years ago

7 0

Answer:

lt the no s be x, x+1 and x+2 then x+(x+1)+(x+2)=72

x+x+x+1+2=72

3x + 3 = 72

3x = 72 - 3

3x = 69 (dividing both sides by "3")

we get x = 23

so the numbers are 23, 24 and 25

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3 years ago

Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems

Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for $(x_{1},y_{1}) and (x_{2},y_{2})$

Use the distance formula to find the length = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point B (4,5) will be point 1 and point C (8,-3) will be point 2

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length = $\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\$

length = $\sqrt{80}$

length = 8.94

Use the distance formula to find the width = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width = $\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\$

width = $\sqrt{(-10 )^{2} + (11 )^{2}}\\$

width = $\sqrt{100 + 121}\\$

width = $\sqrt{221}$

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

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2 years ago