1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
3 years ago
15

9x-4 (x-3)+72 what is X?

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0

Answer:

x = 12

Step-by-step explanation:

9*x-4*(x-3)-(72)=0

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (9x -  4 • (x - 3)) -  72  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  5x - 60  =   5 • (x - 12)

mariarad [96]3 years ago
8 0

Answer:

I think answer is 16.8....

You might be interested in
A cylindrical pressure vessel has a height of 9 feet and a diameter of 6 feet. How much gas can the pressure vessel hold when fu
notka56 [123]

since the diameter of the base of the cylinder is 6 feet, then its radius is half that, or 3 feet.


\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h~~
\begin{cases}
r=radius\\
h=height\\[-0.5em]
\hrulefill\\
r=3\\
h=9
\end{cases}\implies V=\pi (3)^2(9)\implies V=81\pi

5 0
3 years ago
Read 2 more answers
X-4y=-21<br> 8y-x=45<br> Solve the system <br> (X,y)=
meriva

Answer:

\displaystyle (3, 6)

Step-by-step explanation:

{x -4y = −21

{8y - x = 45

_________

\displaystyle \frac{4y}{4} = \frac{24}{4} \\ \\

\displaystyle y = 6[Plug this back into both equations above to get the x-coordinate of 3]; \displaystyle 3 = x

I am joyous to assist you anytime.

6 0
4 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
What is the slope of the graph y=-1
pochemuha
This is a horizontal line passing through  the point (0,-1).

Slope = zero.
4 0
3 years ago
What is the surface area of the cylinder?
ruslelena [56]

A= 3631.68

Step-by-step explanation:

the formula to find the surface area is A=2πrh+2πr^2 so when you substitute all your radius values and height values, you get approximately 3631.68

7 0
3 years ago
Other questions:
  • A rectangular prism has a length of 8 in., a width of 4 in., and a height of 2 1/4 in.
    14·2 answers
  • -77.35 in a fraction
    5·1 answer
  • Zoe's Fish tank holds 27 L of water she uses a 3L container to fill the tank how many times does she have to fill the three litt
    7·1 answer
  • Which if the following is the equation of a line that passes through the points (2,5) and (4,3)
    11·1 answer
  • Last year Golden State Warriors won 80% of the first 15 matches. Then they won the rest of the three matches. What percent of al
    13·2 answers
  • Answer the following question about the function whose derivative is given below
    6·1 answer
  • A number cube is rolled 24 times and lands on a 2 four times and on 6 three times. find the experimental probability of not land
    14·1 answer
  • Which is the simplified form of this expression?
    10·1 answer
  • Working alone, Darryl can mop a warehouse in 11 hours. Elisa can mop the same warehouse in 9
    14·1 answer
  • Pls help me with this
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!