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bixtya [17]
3 years ago
11

How do I make 4(x+3)=3(3x-1) into a simpler form without parentheses. Then substitute 3 for x.

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0
4x+12=9x-3
12+12=27-3
24=24
tamaranim1 [39]3 years ago
3 0

Answer:

x=3

Step-by-step explanation:

1) Expand.

4x+12=9x-34x+12=9x−3

2) Subtract 4x4x from both sides.

12=9x-3-4x12=9x−3−4x

3) Simplify  9x-3-4x9x−3−4x  to  5x-35x−3.

12=5x-312=5x−3

4) Add 33 to both sides.

12+3=5x12+3=5x

5) Simplify  12+312+3  to  1515.

15=5x15=5x

6) Divide both sides by 55.

\frac{15}{5}=x

​5

)

​

​15

​​ =x

7) Simplify  \frac{15}{5}

​5

​

​15

​​   to  33.

3=x3=x

8) Switch sides.

x=3

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution ~

Area of a Trapezoid is :

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}  \times (sum \: of \: parallel \: sides) \times height = 133 \: c {m}^{2}

so ~

\qquad \sf  \dashrightarrow \:  \dfrac{1}{2}  \times ((x + 5) + (3x - 2)) \times (2x - 3) = 133 \:

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\qquad \sf  \dashrightarrow \:  (8 {x}^{2} - 6x - 9)   =( 133  \times 2)\:

\qquad \sf  \dashrightarrow \:  8 {x}^{2} - 6x - 9    =266\:

\qquad \sf  \dashrightarrow \:  8 {x}^{2} - 6x - 9     - 266 = 0

\qquad \sf  \dashrightarrow \:  8 {x}^{2} - 6x - 275 = 0

hence, we got the required equation ~

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