Use the poin-slope form of the equation of a line:-
y - y1 = m(x - x1) (where m = slope and the point is (x1, y1))
Plugging in the given values:-
y - 6 = 2/5(x - 10)
multiplying through by 5:-
5y - 30 = 2(x - 10)
5y - 30 = 2x - 20
5y = 2x + 10
In standard form the equation is
2x - 5y = -10 (answer)
Answer:
E
Step-by-step explanation
24/7+2 = 38/7
if you plus them they are the same
Answer: ![x^{2} = 20y](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%3D%2020y)
Step-by-step explanation:
The directrix given is vertical , so we will use the formula :
![(x-h)^{2}=4p(y-k)](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%3D4p%28y-k%29)
P is the distance between the focus , that is 5 - 0 = 5
Therefore : p = 5
(h,k) is the mid point between the focus and the directrix , that is
(h,k) =
=
= ![(0,0)](https://tex.z-dn.net/?f=%280%2C0%29)
Therefore:
h =0
k = 0
substituting into the formula : we have
![(x-h)^{2}=4p(y-k)](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%3D4p%28y-k%29)
= 4(5)(![y-0)](https://tex.z-dn.net/?f=y-0%29)
![x^{2} = 20y](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%3D%2020y)
Therefore : the equation in vertex form is ![x^{2} = 20y](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%3D%2020y)
Answer:
3 over 2
Step-by-step explanation:
Answer: 48m²
Step-by-step explanation:
We can set up an equation to find the length. Once we have the length, we can multiply it with the width to get out area.
![l=3w](https://tex.z-dn.net/?f=l%3D3w)
![w=4](https://tex.z-dn.net/?f=w%3D4)
Now that we have our length and width, we can plug in width into our length and find the area.
![l=12m](https://tex.z-dn.net/?f=l%3D12m)
![w=4m](https://tex.z-dn.net/?f=w%3D4m)
![A=12m*4m=48m^2](https://tex.z-dn.net/?f=A%3D12m%2A4m%3D48m%5E2)