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lidiya [134]
3 years ago
13

CAN SOMEONEHELP PLS ASAP

Mathematics
1 answer:
Murljashka [212]3 years ago
5 0

Answer:

a ≈ 2.2

Step-by-step explanation:

Using the Cosine rule in Δ ABC

a² = b² + c² - 2bc cos A

Here b = 3, c = 4 and A = 32° , thus

a² = 3² + 4² - (2 × 3 × 4 × cos32° )

    = 9 + 16 - 24cos32°

    = 25 - 24cos32° ( take the square root of both sides )

a = \sqrt{25-24cos32} ≈ 2.2

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write an equation in point-slope form for the line through the given point with the given slope. (8, -3); m= -1/4
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Your answer would be y = (-1/4)x - 1

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3 years ago
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Marizza181 [45]

Answer:

Number of free throws = 155,

Number of two-points field goals= 168

Number of two-points field goals= 124

Step-by-step explanation:

Let x,y, and z be the numbers of free throws, two-point field goals and three-point field goals she made.

As she scored a total of 863 points, so

x+2y+3z=863...(i)

As the number of​ two-point field goals  that Rebecca made was 80 less than double the number of​ three-point field goals she made, so

2z-y=80

Or y=2z-80...(ii)

As the number of free throws​ (each worth one​ point) she made was 13 less than the number of​ two-point field goals she made, so

y-x=13

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-x= 93-2z

x=2z-93...(iii)

Now, put the values from equation (ii) and (iii) to equation (i), we have

(2z-93)+2(2z-80)+3z=863

2z-93+4z-160+3z=863

9z=863+93+160=1116

z=1116/9=124

From equation (ii)

y=2x124-80=168

and from equation (iii)

x=2x124-93=155.

Hence, the number of free​ throws, two-point field​ goals, and​ three-point field goals Rebecca Smith made during the 2006 regular season are 155, 168, and 124 respectively.

4 0
3 years ago
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