The answer is the third one
Answer:
No
Step-by-step explanation:
1 week = 7 days
36 pages x 7 days = 252 pages
257 - 252 = 5
Damita will miss her goal by 5 pages.
Answer: i) θ = 30°, 60°, 210°, & 240°
ii) θ = 20° & 200°
<u>Step-by-step explanation:</u>
i) sin (2θ) = cos 30°
To include all of the solutions for one rotation, add 360/2 = 180 to the solutions above. θ = 30°, 60°, 210°, 240°
If you need ALL of the solutions (more than one rotation), add 180n to the solutions. θ = 30° + 180n & 60° + 180n
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ii) cos α = sin (50 + α)
Use the Identity: cos α = sin (90 - α)
Use Transitive Property to get: sin (50° + α) = sin (90° - α)
50° + α = 90° - α
50° + 2α = 90°
2α = 40°
α = 20°
To find all solutions for one rotation, add 360/2 = 180 to the solution above.
α = 20°, 200°
If you need ALL of the solutions (more than one rotation), add 180n to the solution. α = 20° + 180n
Answer:
C. Cardinality of set E is equal to that of O
Step-by-step explanation:
We are given that two sets
a set E of non negative even numbers
E={0,2,4,....}
A set O of non negative odd numbers
O={1,3,5,.....}
We have to choose correct option in given options
We know that
Set of non negative even numbers is countably infinite and set of non negative odd numbers is also countably infinite.
Cardinality of countably infinite set=Aleph naught=
Therefore, cardinality of E=
Cardinality of O=
Therefore, the cardinality of set E is equal to cardinality of set O.
Hence, option C is true.