Answer:
48f^2-110f+63
Step-by-step explanation:
We multiple every part of first sum with every prt of the 2nd sum:
(6f-7)(8f-9)=48f^2-54f-56f+63=
48f^2-110f+63
So if the bag contains half as many red marbles as blue ones, and there are 8 reds then there are 16 blues. 16 + 8= 24 if you want there to be 1/4 white marbles add 6. 6/30 is 1/4.
So the answer comes out to be 30 marbles in the bag
(?) = (x - 3)(x + 3)
Step-by-step explanation:
[Attached]
Givens
AB + BC = AC
AB = 2(x + 1)
BC = 3x + 1
AC = 4(x + 2)
Substitute and Solve
AB + BC = AC
2(x + 1) + 3x + 1 = 4(x + 2) Remove the brackets on the left
2x + 2 + 3x + 1 = 4(x + 2) Collect the like terms on the left
5x + 3 = 4(x + 2) Remove the brackets on the right.
5x + 3 = 4x + 8 Subtract 4x from both sides.
5x - 4x + 3 = 8
x + 3 = 8 Subtract 3 from both sides
x =8 - 3
x = 5
Answers
AB=2(5 + 1) = 2 * 6 = 12
BC = 3x + 1 = 3*5 + 1 = 15 + 1 = 16
AC = 4(5 + 2) = 4*7 = 28
Answer:
y = 7
Step-by-step explanation:
The straight line which is perpendicular to the y-axis will be either x-axis or parallel to the x-axis.
Now, the general equation for all straight line which is either x-axis or parallel to x-axis are given by y = c ........... (1), where c is any constant.
For c = 0 the line will be x -axis. therefore, y = 0, is the equation of x-axis.
Now, if the line (1) passes through the point (-2, 7), then the equation will be y = 7. (Answer)
{Since, the point (-2,7) will satisfy the equation (1) and then c will be equal to 7.}
