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cluponka [151]
3 years ago
14

What is an example of dealer incentives ?

Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
A car manufacturer giving a car to a dealer in an reduced amount then the actual selling amount with less profit , through which the car dealer is profited and stick to the business and increases sales from his side by which also the manufacturer is also benefited by the dealers action as he get increased sales margin.Typically dealer incentives increase marketing to slow-moving stock after initial sales objectives have been met.
You might be interested in
Which inequality is true when R = 4.6
Nookie1986 [14]

Answer:

A. 3R > 14

Step-by-step explanation:

Here R = 4.6

Now we have to check each options and find which is true.

3R > 14

Dividing both sides by 3, we get

R > 14/3

R > 4.67

Which is true.

All other options are not true.

R + 32 >

R > -32 is not true.

R - 12 < -8

R < +4 is not true.

R/3 < 1

R < 3 is not true.

Hope this will help you.

5 0
3 years ago
What is the approximate value of X? Round to the nearest tenth.
pychu [463]

Answer

Find out the value of x.

To prove

By using the trignometric identity

sin\theta = \frac{Perpendicular}{Hypotenuse}

 As given in the diagram.

\theta = 50 ^{\circ}

Perpendicular = x

Hypotenuse =  6

Put in the above identity

sin\ 50^{\circ} = \frac{x}{6}

sin\ 50^{\circ} = 0.77\ (Approx)

Put in the above

x = 6\times 0.77

x =  4.6 cm (Approx)

Therefore Option (c) is correct .

 

8 0
3 years ago
Read 2 more answers
Help Fast
horrorfan [7]

Answer:

6 square root of 2

Step-by-step explanation:

sin theta = opposite / hypotenuse

sin 45 = 6/x

Multiply by x

x sin 45 = 6

Divide by sin 45

x sin 45/ sin 45 = 6 / sin 45

x = 6/ sin 45

x = 6/ (1/sqrt(2))

x = 6 sqrt(2)

3 0
3 years ago
Read 2 more answers
How to express the radical using the imaginary unit , i. Please help
Hitman42 [59]

Answer:

± 4i\sqrt{5}

Step-by-step explanation:

\sqrt{-80} = \sqrt{16(5)(-1)}

= \sqrt{16} × \sqrt{5} ×\sqrt{-1}

= 4\sqrt{5}i → [ \sqrt{-1} = i ]


3 0
3 years ago
Two pumps connected in parallel fail indepen- dently of each other on any given day. The proba- bility that only the older pump
lions [1.4K]

Answer: 0.145

Step-by-step explanation:

Since,

the Probability of the older pump failing P(fail older) = 0.10

The probability of the newer pump failing P(fail newer) = 0.05

Therefore,

The Probability of the older pump not failing P(not fail older) = 1 - 0.1

P(not fail older) = 0.9

Also,

The probability of the newer pump not failing P(not fail newer) = 1 - 0.05 = 0.95

The probability of the pumping system failing = P(not fail older)* P(not fail newer) = 0.9*0.95

P(not fail system)= 0.855

Therefore,

The probability that the pumping system will fail = 1 - P(not fail system) = 1 - 0.855 = 0.145

The probability that the pumping system will fail one day is 0.145

3 0
3 years ago
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