Question

A population is made up of individuals where 77 have the A1A1 genotype, 65 have the A1A2 genotype, and 123 have the A2A2 genotype. What is the allele frequency of A1? Answer to 2 decimal places.

Answer 1

Answer:

Frequency of allele A1- 0.41

Explanation:

In Hardy weinberg equilibrium,

P refers to the dominant allele

q refers to the recessive allele

The allele frequency will be p+q=1

The genotypic frequency is- P²+q²+2pq=1

P²= genotype of dominant trait ( A1A1)- 77

2pq= genotype of heterozygotes (2pq)- 65

q²= genotype of recessive trait (A2A2)-  123

Total number of offsprings= 77+  65+ 123

                                            = 265

Now to calculate allele frequency of A1=

$\dfrac{\text{number of A1A1 offspring}}{ \text{total number of offspring}}+\dfrac{1}{2}(\dfrac{\text{number of A1A2 offspring}}{\text{total number of offspring}})$

= 77/265 + 1/2( 65//265)

=  0.290+ 0.122

= 0.413

Thus, 0.41 is correct.