0.72
- .20
------------
0.52 (.20 is two tenths)
The answer is 0.3413 because Explanation:
<span>z=<span><span>x−u</span>σ</span></span>, where <span>u=6 0andσ=10</span>.
Therefore the probability student finish the test between 50 to 60 minutes is,
<span>P<span>(50≤x≤60)</span>=P<span>(<span><span>50−60</span>10</span>≤z≤<span><span>60−60</span>10</span>)</span></span>
<span>P<span>(−1≤z≤0)</span>=P<span>(z≤0)</span>−P<span>(z≤−1)</span></span>
<span>=0.5000−0.1587=<span>0.3413</span></span>
It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is 
Likewise, the number of ways a female student can be chosen from 48 females is 
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
Vertical angles are equal
-3x + 58 = x - 2
-3x - x = -2 - 58
-4x = - 60
x = -60/-4
x = 15
m < D = x - 2....15 - 2 = 13 <====
m < C = -3x + 58....-3(15) + 58 = 13
Answer:
The answer is T=-5
Step-by-step explanation:
