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3 years ago

2^5×5×11 and 2^3×5^2×7

Mathematics

1 answer:

IceJOKER [234]3 years ago

4 0

Answer:

1. 1760

2. 1400

Step-by-step explanation:

2^5 = 32

32 × 5 = 160

160 × 11 = 1760

2^3 = 8

5^2 = 25

8 × 25 = 200

200 × 7 = 1400

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Answer:

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Step-by-step explanation:

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$=> \frac{(-3 \times 3) - 11}{21}$

$=> \frac{-9 - 11}{21}$

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Find the additive inverse of $\frac{-20}{21}$ by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of $\frac{-20}{21}$ .

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$=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }$

$=> \frac{9}{5} \times \frac{5}{7}$

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ladessa [460]

The magnitude of -1-5i is √26.

<h3>What is the magnitude of -1-5i ?</h3>

Given the complex expression; -1 - 5i

To find the magnitude, we use the formula;

| a+bi | = √[ a² + b² ]

a = -1
b = -5

| a+bi | = √[ a² + b² ]

| -1-5i | = √[ (-1)² + (-5)² ]

| -1-5i | = √[ 1 + 25 ]

| -1-5i | = √26

Therefore, the magnitude of -1-5i is √26.

Learn more about magnitudes here: brainly.com/question/18152189

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Step-by-step explanation:

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2^5×5×11 and 2^3×5^2×7​

2^5×5×11 and 2^3×5^2×7