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Harrizon [31]
3 years ago
9

True or false please help

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0
I believe it’s true not 100% sure
You might be interested in
Solve for N: 3n - 7 = 6n - 2n
jonny [76]

Answer:

-7

Step-by-step explanation:

1. Combine Like Terms

3n-7=4n

2. Subtract 3n on both sides.

-7=n

3. You got your answer:)

3 0
3 years ago
-2 ×^2 - 4y +6. x=-3. y=-2 <br> evaluate ​
gladu [14]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>-2 ×^2 - 4y +6</u></em>

<em><u>Evaluate simply means to form an idea of something</u></em>

<em><u>So Evaluate for x=−3,y=−2</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>−2(−3)2−(4)(−2)+6</u></em>

<em><u>Answer =−4</u></em>

8 0
3 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
Given that abc is similar to def what is x
solong [7]

since triangles are similar

=》 21/9 = x/3

=》 x = 21×3/9 =7

4 0
3 years ago
You have just completed an experiment measuring the length (in mm) of 12 soybean plants after 3 days of sprouting. The measureme
sweet-ann [11.9K]

Answer:

The new IQR is 22.    

Step-by-step explanation:

We are given the following data of  length (in mm) of 12 soybean plants after 3 days of sprouting.

53, 47, 51, 54, 43, 39, 61, 57, 55, 46, 44, 43

Sorted data:

39, 43, 43, 44, 46, 47, 51, 53, 54, 55, 57, 61

Formula:

IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}  

Median ==\dfrac{6^{th}+7^{th}}{2} \dfrac{47+51}{2} = 49

Q_1 =\dfrac{3^{rd}+4^{th}}{2} = \dfrac{43 + 44}{2} = 43.5\\\\Q_3 =\dfrac{9^{th}+10^{th}}{2}= \frac{54 + 55}{2} = 54.5

IQR = Q_3 -Q_1 =54.5-43.5= 11

If every measurement is doubled, then, the IQR will also double itself.

Thus,

New IQR =

2\times \text{IQR}\\=2\TIMES 11\\=22

Thus, the new IQR is 22.

4 0
3 years ago
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