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asambeis [7]
3 years ago
10

Fred buys candies. He buys 2 candies for a dollar and gets 3 candies free on every purchase

Mathematics
2 answers:
coldgirl [10]3 years ago
6 0

Answer:

The equation for this would be 2d+3 where d is the money spent in dollars.

Step-by-step explanation:

I'm not sure if this is what you where looking for, if not perhaps elaborate on what the question is.

How I got this equation:

For every dollar he gets 2 candies. So you would multiply 2 by the number of dollars. (2d) He also gets 3 more candies per purchase, you add three regardless of money spent, so 3 is added. (+3)

Giving you: 2d+3

Dafna1 [17]3 years ago
4 0

Answer:

Can you finish the question at least?

Step-by-step explanation:

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Whitch ordered pairs are solutions to the inequality y-4x≤-6
konstantin123 [22]

Answer:

y </ 4x - 6

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A drama club made $3,200 from a school play. Seventy-five percent of that amount came from ticket sales. Identify the values of
aev [14]

Answer: $2400

Step-by-step explanation:

Based on the question above, a will be the percentage of tickets that were sold while b will be tickwt sales. Therefore,

a = 75%

b = 75% × $3,200

= 0.75 × $3200.

= $2400

Based on the information above, the amount of tickets sales is $2400

7 0
3 years ago
Find the area of the polygon.
Anastaziya [24]

Answer:

to find the area of a polygon

formula: area = 1/2 x perimeter x apothem

Step-by-step explanation:

Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

5 0
2 years ago
Find the critical numbers of the function f(x) = x6(x − 1)5 what does the first derivative test tell you that the second derivat
patriot [66]
The given function is f(x) = x⁶(x-1)⁵

The first derivative is
f'(x) = 6x⁵(x-1)⁵ + 5x⁶(x-1)⁴
       = x⁵(x-1)⁴(6x - 6 + 5x)
       = x⁵(x-1)⁴(11x - 6)
The critical values are the zeros of f'(x). They are
x = 0, 6/11, and 1.
The critical values indicate that turning points exist for f(x) at the critical points. However, we do not know the nature of the turning points.

Write the first derivative in the form f'(x) = (x-1)⁴(11x⁶ - 6x⁵).
The second derivative is
f''(x) = 4(x-1)³(11x⁶ - 6x⁵) + (x-1)⁴(66x⁵ - 30x⁴)
        = (x-1)³(44x⁶ - 24x⁵ + 66x⁶ - 30x⁵ - 66x⁵ + 30x⁴)
        = (x-1)³(110x⁶ - 120x⁵ + 30x⁴)
        = 10x⁴(x-1)³(11x² - 12x + 3)
The sign of f''(x) at the critical values tell us the nature of the turning point.

f''(0) = 0, therefore a point of inflection exists at x = 0.
f''(6/11) > 0, therefore a local minumum exists at x = 6/11.
f''(1) = 0, therefore a point of inflection exists at x=1.

The graphs shown below confirm these results.

8 0
3 years ago
Pls Help with this Question!
bulgar [2K]
Answer:
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