Question

the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the value of a + b + c ?

Answer 1

Answer:

$a+b+c=32$

Step-by-step explanation:

we have

$(-2x^{2} +x+31)+(3x^{2}+7x-8)$

Adds the terms

Group terms that contain the same variable

$(-2x^{2}+3x^{2})+(x+7x)+(31-8)$

Combine like terms

$(x^{2})+(8x)+(23)$

where

$a=1,b=8,c=23$

therefore

$a+b+c=1+8+23=32$