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3 years ago

Ben has a collection of 240 baseball cards. Of these cards, 30% once played

1 answer:

5 0

Ok so lets start off with calculating the percentage. We have 240 cards so lets find 25% of them so lets use 240 times .25 we get 60 cards then take away 240 - 60 = 180. Next we do the 30% so 240 times .30 would be 72 so take away 180 from 72 thats 108. So there are 108 Houston Astros Cards.

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The figure below is Circle E. Line CF is tangent at point C.

slava [35]

Answer:

Part 1) $m$

Part 2) $m$

Part 3) $m$

Step-by-step explanation:

Part 1) Find the measure of angle ECF

we know that

CF is tangent at point C

the radius EC is perpendicular to the tangent CF

therefore

$m$

Part 2) Find the measure of angle AKB

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite

$m$

substitute the values

$m$

Part 3) Find the measure of angle ACF

we know that

The inscribed angle is half that of the arc it comprises

$m$

substitute the values

$m$

8 0

3 years ago

Read 2 more answers

HELP PLEASE SOON!

kirill115 [55]

$1.\\\\\bold{v_1}=\langle2,4\rangle\qquad\bold{v_2}=\langle-1,5\rangle\\\\
\bold{v_1}\circ\bold{v_2}=2\cdot(-1)+4\cdot5=-2+20=18\qquad [\text{C}]\\\\\\
2.\\\\
\bold{v_1}= \langle2, 5\rangle\qquad \bold{v_2}= \langle4, -3\rangle\\\\\\
\bold{v_1}\circ\bold{v_2}=2\cdot4+5\cdot(-3)=8-15=-7\\\\||\bold{v_1}||=\sqrt{2^2+5^2}=\sqrt{4+25}=\sqrt{29}\\\\
||\bold{v_2}||=\sqrt{4^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5\\\\\\
$

$\cos\Theta=\dfrac{\bold{v_1}\circ\bold{v_2}}{||\bold{v_1}||\cdot||\bold{v_2}||}=\dfrac{-7}{5\cdot\sqrt{29}}\\\\\\
\cos\Theta=-\dfrac{7}{5\sqrt{29}}\quad\implies\quad\Theta=\arccos\left(-\dfrac{7}{5\sqrt{29}}\right)\\\\\\\boxed{\Theta\approx105,1^\circ}$

7 0

4 years ago

Read 2 more answers

Solution A is an $80\%$ acid solution. Solution B is a $30\%$ acid solution. (a) Find the amount of Solution A (in mL) that must

Irina-Kira [14]

Answer:

(a) $2000\text{ ml}$ (b) $40\text{ ml and }60\text{ ml}$ (c)NO

Step-by-step explanation:

GIVEN: Solution A is an $\$80\%$ acid solution. Solution B is a $\$30\%$ acid solution.

TO FIND: (a) Find the amount of Solution A (in mL) that must be added to $500 \text{ml}$ of Solution B in order to produce a $70\%$ acid solution. (b) Find the amount of Solution A and Solution B (in mL) that can be combined in order to form a $100 \text{ml}$ solution that is $50\%$ acid. (c) Does there exist a combination of Solution A and Solution B that is $90\%$ acid.