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kompoz [17]
3 years ago
11

triangle abc is reflected over the line y=x . triangle abc has points a (10,2) , b (9,5) and c (6,4) . what is the c' coordinate

?

Mathematics
2 answers:
Ghella [55]3 years ago
7 0
The coordinates of C are 4,6 because thats the rule for y=x
diamong [38]3 years ago
7 0

Answer:

C'=(4,6)

Step-by-step explanation:

The reflexion of a point P with coordinates (x,y) over the line y=x is the point P' with coordinates (y,x). For example, the reflection point of a with coordinates (10,2) is a' with coordinates (2,10).

For this reason, the point c y reflect in C' with coordinates (4,6).

The solution is also shown in the attachment.

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VikaD [51]

Answer:

I believe that the owner of the dice is actually not lucky. There are people who practice throwing dice in a controlled way in order to get a specific side of the dice. If he practices his dice throwing a lot, then he would have a much higher chance of winning at a game of dice.

Step-by-step explanation:

Since you said he was lucky, I decided to make an answer saying that he wasn't lucky so you can choose between both of them. Your answer was good as well.

7 0
2 years ago
$4000 for 2years at 5% compounded quarterley
NeTakaya
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, meaning 4 times}
\end{array}\to &4\\

t=years\to &2
\end{cases}
5 0
3 years ago
Use the triangle at the right. find the length of the missing side
mario62 [17]

3.0 NOT SURE IF ITS CORRECT


8 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

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3 years ago
If you spend $3 on 6 apples what is the unit rate? Or in other words, what is the cost of each apple?
Andrew [12]

Each apple costs .50 cents :D

8 0
3 years ago
Read 2 more answers
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