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3 years ago

Which triangle defined by three points on the coordinate plane is congruent with the triangle illustrated, and why?

2 answers:

4 0

The triangle defined by three points on the coordinate plane is congruent with the triangle illustrated:

C) (4,2); (8,2); (4,8) because the corresponding pairs of sides and corresponding pairs of angles are congruent.

If we plot these points we can observe that they are congruent, we should also solve for the distance of each point between each other to conclude their congruency.

Harlamova29_29 [7]3 years ago

3 0

The correct answer is D..........

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For f(x)=x^2, sketch the graph of g(x)=f(2x+6)

N76 [4]

Answer:

See image

Step-by-step explanation:

g(x) is a transformed version of f(x), its 6 units to the left with a verticle strech of a factor of 2

5 0

3 years ago

A total of 5000 is invested part at 10% and the remainder at 15%. How much is invested at Each rate if the annual interest is $6

vekshin1

Answer:Let the amount invested in each be

A and B

A+B=5000

0.1A+0.15B=630

0.1(5000-B)+0.15B=630

500-0.1B+0.15B=630

0.05B=130

B=2600

A=2400

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP WILL MARK AND 5 STARS I BEG OF U

jek_recluse [69]

Answer:

X=120

X=54

Step-by-step explanation:

(this is for the top one and the one below the top one)

(I think they are right)

3 0

3 years ago

Read 2 more answers

Can someone please help me with math.

MaRussiya [10]

Answer:

1. Binomial

2. Binomial

3.Polynomial

4. Constant

5.Trinomial

6. Trinomial

Monomial- consists of one term

Binomial- consists of two terms separated by a plus or minus sign

Trinomial- consists of three terms separated by a plus or minus sign

Polynomial- consists of 4+ terms separated by a plus or minus sign

Constant- a number such as 130

3 0

3 years ago

A random sample of 49 statistics examinations was taken. the average score, in the sample, was 84 with a variance of 12.25. the

tester [92]

Since in this case we are only using the variance of the sample and not the variance of the real population, therefore we use the t statistic. The formula for the confidence interval is:

Where,

X = the sample mean = 84

t = the t score which is obtained in the standard distribution tables at 95% confidence level

s = sample variance = 12.25

n = number of samples = 49

From the table at 95% confidence interval and degrees of freedom of 48 (DOF = n -1), the value of t is around:

t = 1.68

Therefore substituting the given values to equation 1:

CI = 84 ± 1.68 * 12.25 / sqrt(49)

CI = 84 ± 2.94

CI = 81.06, 86.94

<span>Therefore at 95% confidence level, the scores is from 81 to 87.</span>

6 0

3 years ago