Daddy is the answer sissy imposter
First we find out what percent the sale price is of the original price.
0.15 / 0.75 x 100 = 20%
Then we subtract this from 100% to get the discount:
100 - 20 = 80% discount
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
I think it’s 4
0+8x=23+2x
6x=23
x=3,8333
Answer:
probably 57 will be the answer