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3 years ago

7

Please help meeee I’m stuck only if you know geometry

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer:

Step-by-step explanation:

You can see by the markings that ST is congruent to AY, and that TA is congruent to YS. Those are 2 sides, so so far we have SS. One important thing that comes up WAY TOO OFTEN IN GEOMETRY TO IGNORE is the fact that both of those triangles share the side SA. This is called the reflexive property. The theorem for congruency between these 2 triangles is SSS.

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Each year a store decrease the price of a certain model of a TV by $35 if the price in 2001 was $1950 what is the price in 2009

Ronch [10]

Answer:

1,670

Step-by-step explanation:

35x8= 280

1950-280= 1,670

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4 years ago

13) -3x - 4y = 8<br>-4x - 3y=6

Dvinal [7]

Answer:

x = 0, y = -2

Step-by-step explanation:

-3x - 4y = 8 (1)

-4x - 3y=6 (2)

Multiply (1) by -4 and (2) by -3, we have:

12x + 16y = - 32 (3)

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Subtract (4) from (3), we have:

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4 years ago

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vekshin1

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Step-by-step explanation:

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4 years ago

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3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago