All categories

4 years ago

435 is 15% of what number?

Mathematics

1 answer:

melamori03 [73]4 years ago

7 0

435 is 15% of 2900 that is the answer

You might be interested in

Write and solve an equation to find the value of x and the missing angle measures

Alinara [238K]

Answer:

85 degrees

Step-by-step explanation:

its really easy just make them equal to eachother and then solve

9x + 13 = 11x-3

-11x (subtract because 11x is positive)

-2x +13 = -3

-13 (subtract because 13 is positive)

-2x = -16

divide both sides by -2

x= 8

substitute 8 for the x's and you have your answer

8 0

3 years ago

What is the answer to 82.75 = -37

Tom [10]

<h3>Answer: Well the question is kind of confusing but here's how I see it</h3>

82.75

_______

45.7 <----- The answer

Hope this helps;

Have a cooke :D

8 0

3 years ago

What is 3(x - 1) = 2x + 9

notsponge [240]

Answer:

x=12

Step-by-step explanation:

Distribute:

3x - 3 = 2x + 9

Combine like terms to one side:

x = 12

6 0

3 years ago

Read 2 more answers

Can someone answer this o

nikitadnepr [17]

Answer:

x>125

Step-by-step explanation:

multiply the denominator 25 on both sides

the "x" should cancel out

and then you would get x>125

3 0

3 years ago

Read 2 more answers

Solve the radical equation. square root 6n-11= n – 3 Which solution is extraneous? A.)2

Anvisha [2.4K]

ANSWER

D) 10

EXPLANATION

We want to solve the radical equation,

$\sqrt{6n - 11} = n - 3$

Square both sides,

$6n - 11 = (n - 3) ^{2}$

Expand brackets on right hand side,

$6n - 11 = {n}^{2} - 6n + 9$

Rewrite in general quadratic equation form,

${n}^{2} - 12n + 20 = 0$

Factor to obtain,

$(n - 2)(n - 10) = 0$

Apply the zero product principle to get,

$n = 2 \: or \: n = 10$

We put n=2 into the equation to get,

$\sqrt{6(2) - 11} = 2 - 3$

$1 = - 1$

This statement is false, hence 2 is an extraneous solution

We put n=10, to get

$\sqrt{6(10) - 11} = 10 - 3$

$\sqrt{49} = 7$

$7 = 7$

This is true, hence the only solution is
$n = 10$

3 0

4 years ago

Read 2 more answers