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forsale [732]
3 years ago
9

A rock band has made souvenir T-shirts to sell at their concert and hopes to bring in at least $140 from the sale of the shirts.

They make $4 for each adult T-shirt and $2 for every child T-shirt. I have to write a linear equation
Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0
A = amount of adult shirts sold
c = amount of child shirts sold

140 = 4a + 2c
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A + b = dr, solve for a
AURORKA [14]

Hey there!

Since we don't have values for b, d, and r, we can't get a specific number for the value of a, if that makes sense. It'll be represented by these variables.

To solve, we need to make sure the equation looks like a = ? .

Subtract b from each side of the equation.

<u>a = dr - b </u>

Now we have solved for a.

Hope this helps!

6 0
3 years ago
The points in the table lie on a line. What is the slope of the line?
Elanso [62]
The slope of the line is -7/6
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2 years ago
24. DESS SENSE-MAKING Two times the least of three consecutive odd integers exceeds
lilavasa [31]

Answer:

-27, -25, -23

Step-by-step explanation:

Let the three consecutive odd integers be:

First integer = a

Second integer = a + 2

Third integer = a + 4

Two times the least integer = 15 + three times the greatest

2a = 3(a + 4) + 15

2a = 3a + 12 + 15

2a - 3a = 27

a = -27

So the first integer is -27, the second integer is -25 and the third integer is -23.

5 0
2 years ago
Choose the correct product of (9x − 5)(9x + 5).
Virty [35]
Hi,
(a+b)(a-b=a²-b²
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4 0
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Read 2 more answers
An airplane is preparing to land at an airport. It is 44,8000 feet above the ground and is descending at the rate of 3,100 feet
Marina86 [1]

Answer:

Time: 8 minutes

Altitude: 20000ft

Method 1 is easiest

Method 3 is easiest

Step-by-step explanation:

Given

Airplane 1:

Height = 44800 ft

Descending\ Rate = 3100ft/min

Airplane 2:

Ascending\ Rate = 2500ft/min

Required

Determine when both planes would be at the same altitude?

Let the minute be represented by m

For Airplane 1, Its altitude at any height h is:

Airplane\ 1 = Height - Descending\ Rate * m

<em>It is minus (-) because the airplane is descending</em>

Airplane\ 1 = 44800 - 3100 * m

Airplane\ 1 = 44800 - 3100m

For Airplane 2, Its altitude at any height h is:

Airplane\ 2 = Ascending\ Rate * m

Airplane\ 2 = 2500 * m

Airplane\ 2 = 2500m

Method 1:

For both heights to be equal, we have that:

Airplane\ 1 = Airplane\ 2

This gives:

44800 - 3100m = 2500m

Collect Like Terms

44800 = 2500m + 3100m

44800 = 5600m

5600m = 44800

m = 44800/5600

m = 8\ min

<em>Hence, the time they will be at the same altitude is 8 minutes</em>

Substitute 8 for m in

Airplane\ 2 = 2500m

Airplane\ 2 = 2500 * 8

Airplane\ 2 = 20000\ ft

<em>Hence, they will be at the same altitude at 20000ft</em>

Method 2:

We have that:

Airplane\ 1 = 44800 - 3100m

Airplane\ 2 = 2500m

Since they are to be at the same altitude, then

The difference in their altitude must be 0

i.e.

Airplane\ 1 - Airplane\ 2 = 0

This gives

44800 - 3100m - 2500m = 0

44800 - 5600m = 0

Collect Like Terms

5600m = 44800

m = 44800/5600

m = 8\ min

Substitute 8 for m in

Airplane\ 1 = 44800 - 3100m

Airplane\ 1 = 44800 - 3100 * 8

Airplane\ 1 = 44800 - 24800

Airplane\ 1 = 20000\ ft

Method 3:

We have that:

Airplane\ 1 = 44800 - 3100m

Airplane\ 2 = 2500m

Since they are to be at the same altitude, then

The ratio of their altitudes must be 1

i.e.

\frac{Airplane\ 1}{Airplane\ 2} = 1

\frac{44800 - 3100m}{2500m} = 1

Cross Multiply

44800 - 3100m = 1 * 2500m

44800 - 3100m = 2500m

Collect Like Terms

44800 = 2500m + 3100m

44800 = 5600m

5600m = 44800

m = 44800/5600

m = 8\ min

Substitute 8 for m in

Airplane\ 1 = 44800 - 3100m

Airplane\ 1 = 44800 - 3100 * 8

Airplane\ 1 = 44800 - 24800

Airplane\ 1 = 20000\ ft

Hence;

<em>Their altitudes must be 20000ft</em>

<em>Though the three methods applied uses the same logic at some point, the first method applied is still the easiest and it is a straight forward method that could be applied in solving the question.</em>

<em>Method 3 is the most difficult.</em>

7 0
3 years ago
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