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kvasek [131]
2 years ago
8

In the year 2005, a total of 750 fish were introduced into a manmade lake. The fish population was expected to grow at a rate of

8.3% each year.
What will the fish population be in 2050?

Round to the nearest whole number.

Enter your answer in the box.
Mathematics
2 answers:
tangare [24]2 years ago
8 0
The population of the fish is given by P(t) = 750(1 + 0.083)^t; where t is the number of years after 2005.
Here, t = 2050 - 2005 = 45

Population in 2050 = 750(1.083)^45 = 750(36.16) = 27,123
sweet [91]2 years ago
4 0

Answer:

27,123

Step-by-step explanation:

took the test its correct


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Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
When figuring the pooled population variance estimate in a t test for independent means?
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The appropriate response is a weighted average. It is a mean ascertained by giving qualities in an informational index more impact as indicated by some characteristic of the information. It is normal in which every amount to have arrived at the midpoint of is allocated a weight, and these weightings decide the relative significance of every amount on the normal.
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What are the x-intercepts of the graph of the quadratic function
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(Make sure to set f(x) to zero)

So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: 0=5x^2+5x-x-1

Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: 0=5x(x+1)-1(x+1)

Now you can rewrite the equation as: 0=(5x-1)(x+1)

Now apply zero product property to the factors to solve for x:

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<u>The x-intercepts are (1/5 ,0) and (-1,0).</u>

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Answer:

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Step-by-step explanation:

To find the cos (C) we must use the cosine theorem.

The cosine theorem says that:

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In this case:

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So

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cos(C) = -\frac{9^2- 40^2- 41^2}{2(40)*(41)}

cos(C) =\frac{40}{41}\\\\cos(C)=0.976

7 0
3 years ago
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