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yuradex [85]
3 years ago
7

U^2+u-72/3u-15 need to factor completely

Mathematics
1 answer:
lesya [120]3 years ago
3 0
U^2+u-72/3u-15 

u^2+u-24u-15
 

u^2-23u-15
  
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X/3=-7<br><br> find the variable
rjkz [21]

Answer:

x=−21

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the answer for this
Leviafan [203]
I think that
the triangle is 6
the square is -5
and the star is -20
but i would get a second answer bc i cant certainly say that<span />
6 0
3 years ago
Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).
Leni [432]

Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

m_1=\frac{7-0}{3-0}=\frac{7}{3}

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)

The slope of the line joining E(7,0), and F(3,7). is:

m_1=\frac{7-0}{3-7}=-\frac{7}{4}

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:

x = 3, y = 1.7

4 0
3 years ago
A long distance runner starts at the beginning of a trail and runs at a rate of 4 miles per hour. One hour later, a cyclist star
Scrat [10]
T = 1/4 hour will be the answer
7 0
3 years ago
Which zero pair could be added to the function f(x)=x^2+12x+6 so that the function can be written in vertex form?
andrew11 [14]
<span>f(x) = x</span>² <span>+ 12x + 6  </span>→ y = x² + 12x + 6<span>

Let us convert the standard form into vertex form.

1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side. 

y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30  ← Vertex form
<span>
To check:

y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>

The zero that could be added to the given function is 36, -36</span>
4 0
3 years ago
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