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nignag [31]
3 years ago
8

If yesterday's day after tomorrow is Sunday, what day is tomorrow's day before yesterday?

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

friday

Step-by-step explanation:

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Hi can you please help I’ve been stuck on this question
sveta [45]

9514 1404 393

Answer:

  20 meters

Step-by-step explanation:

Using the formula for the area of a rectangle, fill in the given information and solve for the unknown.

  A = LW . . . . . . . . area is length × width

  80 m² = L·(4 m)

  (80 m²)/(4 m) = L = 20 m . . . . . . . divide by 4m (the coefficient of L)

The tarp is 20 meters long.

4 0
3 years ago
What is the perimeter of this shape?
PSYCHO15rus [73]

<u>Given</u>:

Given that the sides of the shape.

The given shape consists of 8 sides.

We need to determine the perimeter of the given shape.

<u>Perimeter</u>:

The perimeter of the figure can be determined by adding all the lengths of the sides of the shape.

Thus, we have;

Perimeter=10+4+2+4+6+4+2+4

Adding the values, we get;

Perimeter = 36

Thus, the perimeter of the given shape is 36 feet.

5 0
3 years ago
Read 2 more answers
A new club sent out 172 coupons to boost sales for next year's memberships. They provided 3 times as many to potential members
cricket20 [7]

Answer: 172: 4= 43

43× 3= 129

172-129= 43

Odp.Wysłali 43 kupony do istniejących członków.

Step-by-step explanation:1.bo wysłali 3×wiecej i jeszcze są istniejący członkowie

2.ile wyslali potencialnym

3.i ile wyslali do istniejacych

4 0
4 years ago
Which strategy best explains how to solve this problem?
Rufina [12.5K]
This is a geometric sequence because each term is twice the value of the previous term.  So this is what would be called the common ratio, which in this case is 2.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1)  so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r)  where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so 

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.
4 0
3 years ago
Read 2 more answers
Help pls helpppp me plssssssssssss
AleksAgata [21]
5.C
6.D
I hope you get it correct
6 0
3 years ago
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