<span>A. periodic; about 6</span>
Answer:
Step-by-step explanation:
WE are given that
. Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then




Note that as n increase,
gets closer to 0. So, the limit of this sequence is 0.
Answer:
40
Step-by-step explanation:
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
Answer:
16, 56, ...
Step-by-step explanation:
It looks like you have to put in each cell the multiplication of the row and the column, so the columns are 2, 7, 4 etc., and the row is always 8.
First cell: 2x8 = 16
Second cell: 7x8 = 56
and so on
It teaches you to apply the multiplication in a random sequence; you should be able to do this in your head.
Im pretty positive that it is 93/44