Answer:
The ratio of sanstone to marble is... 141414 : 333
All you have to do is look at how much sandstone Dean has and how much marble he has, then put the amount of sandstone infront of the amount of marble because in the question it says what is the ratio of sandstone to marble and you see that sandstone is first.
Hope this helps! :)
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Answer:
The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
Step-by-step explanation:
We are given that
Mean, ![\mu=8.04 g](https://tex.z-dn.net/?f=%5Cmu%3D8.04%20g)
Standard deviation, ![\sigma=0.08g](https://tex.z-dn.net/?f=%5Csigma%3D0.08g)
We have to find the two weights that separate the top 3% and the bottom 3%.
Let x be the weight of machine components
![P(Xx_2)=0.03](https://tex.z-dn.net/?f=P%28X%3Cx_1%29%3D0.03%2C%20P%28X%3Ex_2%29%3D0.03)
![P(X](https://tex.z-dn.net/?f=P%28X%3Cx_1%29%3DP%28Z%3C%5Cfrac%7Bx_1-8.04%7D%7B0.08%7D%29)
=0.03
From z- table we get
![P(Z1.88)=0.03](https://tex.z-dn.net/?f=P%28Z%3C-1.88%29%3D0.03%2C%20P%28Z%3E1.88%29%3D0.03)
Therefore, we get
![\frac{x_1-8.04}{0.08}=-1.88](https://tex.z-dn.net/?f=%5Cfrac%7Bx_1-8.04%7D%7B0.08%7D%3D-1.88)
![x_1-8.04=-1.88\times 0.08](https://tex.z-dn.net/?f=x_1-8.04%3D-1.88%5Ctimes%200.08)
![x_1=-1.88\times 0.08+8.04](https://tex.z-dn.net/?f=x_1%3D-1.88%5Ctimes%200.08%2B8.04)
![x_1=7.8896](https://tex.z-dn.net/?f=x_1%3D7.8896)
![\frac{x_2-8.04}{0.08}=1.88](https://tex.z-dn.net/?f=%5Cfrac%7Bx_2-8.04%7D%7B0.08%7D%3D1.88)
![x_2=1.88\times 0.08+8.04](https://tex.z-dn.net/?f=x_2%3D1.88%5Ctimes%200.08%2B8.04)
![x_2=8.1904](https://tex.z-dn.net/?f=x_2%3D8.1904)
Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
Multiply 80 by 5/8ths.
80*5/8=50
Answer:
When x = 3
f(3) = 3 + 7 = 10
When x = -5
f(-5) = -5 + 7 = 2
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