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Iteru [2.4K]
3 years ago
9

How can prime factorization help assist with LCM and GCF?

Mathematics
1 answer:
Ghella [55]3 years ago
7 0
I hope this helps you

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Pls pls help I’m really confused could someone explain to me pls
kenny6666 [7]
Answer: 11.6

--------------------------------------

Explanation:

See the attached image for a visual reference

The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)

We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is 
AD = x
Because AD is another radius of the same circle

Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to 11.6 when rounding to the nearest tenth (one decimal place)

3 0
3 years ago
Colleen says she is thinking of a 4 digit number im which all the digits are the same. The value of the digit in the hundreds pl
uysha [10]

Well, the number should be 2,222 since she wants the hundreds place to be a 2, being worth 200. Since she wanted all the digits to have the same number, it would be 2,222 for your final answer.

Hope this helped!

Nate

7 0
3 years ago
Triangle QRS has been translated to create triangle Q'R'S'. RS= R'S' = 10 units, QS= Q'S' = 5 units, and angles Q and Q' are bot
const2013 [10]
It would be ASA(angle side angle)

if 2 angles and an included side are congruent, then the two triangles are congruent.
5 0
3 years ago
Read 2 more answers
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
What number is a factor of 24 but not a multiple of 12 Answer choices A) 8 B) 9 C) 5 D)
schepotkina [342]
It’s A because 3 8’s are 24 but it’s not a mulitiple of 12
5 0
3 years ago
Read 2 more answers
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