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vampirchik [111]
1 year ago
13

Tracy invests $1,000 into a mutual fund which

Mathematics
1 answer:
dezoksy [38]1 year ago
7 0
$2800

Please mark brainliest
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expeople1 [14]
The lease common denominator using prime factorization would be 2. 2 is the number they can both be divided by and is also a prime number
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3 years ago
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Two one-step equations
olchik [2.2K]

Question:  When is this due?                                      

6 0
1 year ago
Find a fraction or mixed number that is between the two numbers -3/4 -1/3
Mandarinka [93]

Hey there!


-3/4 - 1/3

= -3/4 + (-1/3)

≈ -9/12 - 4/12

= -9 - 4 / 12 - 0

≈ -9 - 4 / 12

= -13 / 12

≈ -1 1/12


Therefore, your answer is/

-13/12 or -1 1/12

EITHER OF THOSE SHOULD BE CORRECT BECAUSE THEY ARE EQUIVALENT OR THE SAME THING.


Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

6 0
2 years ago
The hypotenuse of one side of a right angled triangle are 5cm and 4cm respectively. what is the length of the other side
AURORKA [14]
Answer: 3cm

Explanation:

We can use Pythagorean’s theorem to find that other side:

a^2 + b^2 = c^2
a^2 + 4^2 = 5^2
a^2 = 25 - 16
a^2 = 9
a = 3

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3 0
3 years ago
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Find all solutions of the equation in the interval [0, 2pi).
natali 33 [55]

Answer:

Step-by-step explanation:

Begin by squaring both sides to get rid of the radical. Doing that gives you:

sin^2x=1-cosx

Now use the Pythagorean identity that says

sin^2x =1-cos^2x and make the replacement:

1-cos^2x=1-cosx. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:

1-cos^2x+cosx-1=0 and then simplify to

cosx-cos^2x=0

Factor out the common cos(x) to get

cosx(1-cosx)=0 and there you have your 2 trig equations:

cos(x) = 0 and 1 - cos(x) = 0

The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at

x=\frac{\pi }{2},\frac{3\pi}{2}

The second equation simplifies to

cos(x) = 1

Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.

So, in the end, your 3 solutions are

x=\frac{\pi}{2},\pi,\frac{3\pi}{2}

8 0
3 years ago
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