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Lina20 [59]
2 years ago
6

Milli plans to rent a room for her birthday party for $40. The catering charge is $12 per person but there is no charge for Mill

i's meal since she is the guest of honor. If Milli has $100 to spend on her birthday party, how many guests can she invite?
Mathematics
1 answer:
joja [24]2 years ago
7 0
Since Milli has $100 to spend on her birthday party and she will pay $40 so the remaining money left for her party is $60. For the $60 left she will then pay $12 for each guest for catering. Divide $60 by $12, the answer is 5. Therefore Milli will have 5 guests for her birthday. 
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A, B and C

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Answer:

  16x² +48x +36

Step-by-step explanation:

A perfect square trinomial is of the form ...

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We want to match this form.

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<h3>comparing terms</h3>

Comparing the known terms, we see ...

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<h3>filling in the missing term</h3>

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4 0
2 years ago
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

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=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

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