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3 years ago

Write a real world problem that can be solved using the equation, 5x = 3x + 20

Mathematics

1 answer:

Natali5045456 [20]3 years ago

8 0

-3x from both sides so it looks like 2x=20 and divide by 2 and x=10

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If a person takes a jump which is half a feet and then gets tired so he takes another jump which is half if the first jump and h

patriot [66]

He will never reach the full foot, this is because if he travels 1/2 of the distance of the previous jump each time there will always be a fraction that is unaccounted for.

3 0

3 years ago

Read 2 more answers

Please help

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0

2 years ago

Solve the equation. Explain each step and identify the property used to reach each step.

Tom [10]

To isolate x, we will first subtract 0.8 from both sides.

0.6x + 0.8 = 1.4

-0.8 -0.8

0.6x = 0.6

Now all we have to do is divide both sides by 0.6, because it is the number besides x.

0.6x/0.6 = 0.6/0.6

x = 1

So you get the answer of x = 1.

7 0

2 years ago

Which of the following is equivalent to? 19

11Alexandr11 [23.1K]

Answer:

we dont see the numbers

Step-by-step explanation:

3 0

2 years ago

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What is the solution to the following equation? x2 + 3x + 4 = 0

andreev551 [17]

Answer:

$x=\dfrac{-3\pm \sqrt7i}{2}$

Step-by-step explanation:

The given equation is $x^{2}+3x+4=0$ .

We need to find the solution of the above equation.

The solution of an equation $ax^2+bx+c=0$ is :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

We have, a = 1, b = 3 and c = 4

$x=\dfrac{-3+ \sqrt{(3)^2-4(1)(4)} }{2}, \dfrac{-3- \sqrt{(3)^2-4(1)(4)} }{2}\\\\=\dfrac{-3+\sqrt{9-16}}{2}, \dfrac{-3-\sqrt{9-16}}{2}\\\\=\dfrac{-3\pm \sqrt7i}{2}$

So, the solution of the given equation is $\dfrac{-3\pm \sqrt7i}{2}$ .

5 0

3 years ago