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motikmotik
3 years ago
7

A tree casts a shadow that is 8 feet long, a 3 foot mailbox cast a shadow that is 5 feet long. how tall is the tree?

Mathematics
1 answer:
madam [21]3 years ago
7 0
Set up two fractions:
8/x and 3/5
Set them equal to each other and cross multiply to get:
8*5 = 3x
40 = 3x
13.3 = x or 13 and 1/3 feet tall. 
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Order of operations
timurjin [86]

Answer:

z+9(8−x)+8(z+8)=

z+72-9x+8z+64=

9z-9x+136

<u>                                                                    </u>

(3−10)^2−(5−12)^2     parenthesis first

(-7)²-(-7)²=

49-(49)=49-49=0

<u>                                                                       </u>

2^2⋅4^3      exponent first

2*2*4*4*4

4*64=256  

6 0
3 years ago
What is 6 times less 420
alexandr1967 [171]
The correct answer is 70 because 420 divided by 6 is 70.
8 0
3 years ago
How much cardboard needed to construct a rectangular prism measuring 15 inches by 13 inches by 7 inches
aleksandrvk [35]
1,365

hopefully, this helps

4 0
3 years ago
Sofia is planning her physical activities for the week and wants to choose an activity that will help her build stamina. She sho
BigorU [14]
Strengthens leg muscles and includes cardio
8 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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