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iragen [17]
3 years ago
7

the cost of using broadband in a hotel is £30 per hour formula to work out this total this total cost is cost in pounds = 3× num

ber of hours. Workout the total of using boardband for 2 hours and 5 hours​
Mathematics
2 answers:
adoni [48]3 years ago
4 0

Answer:

10

Step-by-step explanation:

andrezito [222]3 years ago
4 0
It’s 10

Please mark me as brainlist
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Solve the Inequality for x<br> x/2+3/2&lt;5/2
charle [14.2K]

Answer:

x<2

Step-by-step explanation:

I didnt feel like typing it out but the explanation is in the picture hope this helps :)

7 0
3 years ago
A 12 vdc power supply powers a blue high intensity led with a forward voltage of 4.5 volts. The led is rated to withstand a maxi
dimulka [17.4K]

Answer:

Resister of 0.15 W is to be added.

Step-by-step explanation:

In a given circuit we have the attachments

A power supply of 12 V

High intensity LED with forward voltage = 4.5V

LED is rated to withstand a maximum current of 20 mA or 20.10^{-30} A

We have to calculate the size of a resister to be connected in series.

Here we will apply the Ohm's law for the calculations

Total voltage of the circuit = voltage of LED + voltage across resistance.

12=4.5+20.10^{-3}.r

r = (12 - 4.5)/20.10^{-3}

r = 7.5×10^{3}/20 = 375 ohm

Therefore power of the resistance = i².r

P=i^{2}\times r

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        = 0.15 W

Therefore a resister of 0.15 W is to be added.

6 0
3 years ago
(1 point) Some shrubs have the useful ability to resprout from their roots after their tops are destroyed. Fire is a particular
ziro4ka [17]

Answer:

The answer is "0.45 \pm 0.18204"

Step-by-step explanation:

For the +4 sample proportion= \frac{(7+2)}{(16+4)} =  \frac{9}{20} = 0.45

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= \sqrt{\frac{[(0.45)(1-0.45)]}{[(16+4)]}}\\\\ = \sqrt{\frac{[(0.45)(0.55)]}{[(20)]}}\\\\ = \sqrt{\frac{0.2475}{20}}\\\\= \sqrt{0.012375}\\\\=0.111

Calculating the critical z for a=0.1, two-tailed = 1.64

Calculating the confidence interval:

= 0.45 \pm 0.111 \times 1.64 \\\\= 0.45 \pm 0.18204

4 0
3 years ago
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tatyana61 [14]

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3 years ago
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Area of shaded region of a rectangle
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u forgot to add the pic lma.o.

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