1) Surface Area = 2(lw + lh + wh)
2(4*5+4*9+5*9) =202in^2
Surface Area=202in^2
Lateral Area= Perimeter of base * height
5+5=10 <--width+width
4+4=8 <---length + length
10+8=18 <--total perimeter
18 * 9=162in^2 <--multiplied the height +perimeter of base
Lateral Area=162in^2
2) Same concept as the previous one
Surface Area = 2(lw + lh + wh)
2(4*2+4*5+5*2) =76in^2
Surface Area= 76in^2
Lateral Area
Lateral Area= Perimeter of base * height
4+4=8
2+2=4
8+4=12
12 x 5=60
Lateral Area= 60in^2
Answer:
D
Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (y, - x ) , thus
X(- 1, - 3 ) → X'(- 3, 1 )
Y(0, 0 ) → Y'(0, 0 )
Z(1, - 3 ) → Z'(- 3, - 1 )
Answer:
(4, 0)
Step-by-step explanation:
given the 2 equations
y = x - 4 → (1)
- 4x - 6y = - 16 → (2)
substitute y = x - 4 into (2)
- 4x - 6(x - 4) = - 16
- 4x - 6x + 24 = - 16
- 10x + 24 = - 16 ( subtract 24 from both sides )
- 10x = - 40 ( divide both sides by - 10 )
x = 4
substitute x = 4 into (1) for corresponding value of y
y = 4 - 4 = 0
solution is (4, 0)