Question

John is 3 years older than Jim. Jim is 4 years less than twice David’s age. How old are the three boys if their ages add up to 35?

Answer 1

Answer:

15  years , 12  years , 8 years.

Step-by-step explanation:

Given:

John is 3 years older than Jim.

Jim is 4 years less than twice David’s age.

Ages of three boys add up to 35.

Question asked:

How old are the three boys?

Solution:

Let age of David = $y$

Let age of Jim = $x$

Then age of John will be = $x + 3$

As Jim is 4 years less than twice David’s age

Equation will be  , $x = 2y - 4$

Multiplying both side  by 2

                       = $2x = 4y - 8$  (let equation 1 )

As ages of three boys add up to 35.

Equation will be,$x + (x + 3) + y = 35$

                           = $2x + 3 + y = 35$

Subtracting both side by 3

                           =   $2x + y = 32$

                          = $2x = - y + 32$  (let equation 2 )

subtracting equation 1 and 2,we get

                           =  $2x = - y + 32$

                          =   $2x = 4y - 8$

                          =  $0 = - 5y + 40$

                          = $5y = 40$

dividing both side by 5

                              $= y = 8$ (David ages)

Then  ( age of Jim)  $x = 2y - 4$

                                 $x = 2 \times8 - 4$

                                    = $16 - 4$

                                    = $12 years$

Then age of John will be, $x + 3$

                                            $= 12 + 3$

                                            = $15 years$

Thus, age of John = 15 years

Age of Jim = 12 years

Age of David = 8 years