I think the answer is $166,742.24
I think that its d seems like it might hope this is right
Answer:
The area of an octagon whose perimeter is 120 cm is 1086.4 ![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Step-by-step explanation:
An octagon is a polygon with eight sides. If the lengths of all the sides and the measurement of all the angles are equal, the octagon is called a regular octagon.
There is a predefined set of formulas for the calculation of perimeter, and area of a regular octagon.
The perimeter of an Octagon is given by
![P=8a](https://tex.z-dn.net/?f=P%3D8a)
and the area of an Octagon is given by
![A=2a^{2}(1+\sqrt{2})](https://tex.z-dn.net/?f=A%3D2a%5E%7B2%7D%281%2B%5Csqrt%7B2%7D%29)
We know that the perimeter is 120 cm, solving for side length (a) in the perimeter formula we get
![120=8a\\\frac{8a}{8}=\frac{120}{8}\\a=15](https://tex.z-dn.net/?f=120%3D8a%5C%5C%5Cfrac%7B8a%7D%7B8%7D%3D%5Cfrac%7B120%7D%7B8%7D%5C%5Ca%3D15)
Now, we calculate the area
![A=2a^{2}(1+\sqrt{2})\\A=2(15)^{2}(1+\sqrt{2})\\A=450\left(1+\sqrt{2}\right)\\A\approx 1086.4 \:cm^{2}](https://tex.z-dn.net/?f=A%3D2a%5E%7B2%7D%281%2B%5Csqrt%7B2%7D%29%5C%5CA%3D2%2815%29%5E%7B2%7D%281%2B%5Csqrt%7B2%7D%29%5C%5CA%3D450%5Cleft%281%2B%5Csqrt%7B2%7D%5Cright%29%5C%5CA%5Capprox%201086.4%20%5C%3Acm%5E%7B2%7D)
Check the attached file for the answer.
-4.5 might be the answer im not very sure but yeah