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3 years ago

if there are 170 students in 12th grade, what percentage of the twelfth grade students have more than one college in mind

1 answer:

5 0

The answer is 31 because the ones that have two colleges is 27 and the ones that have three colleges or more is 23. And if there is 170students you would add the 23+27=53 and divide that by 170.
53/170=31

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ben works at the movie theather and earns d dollars per year. He gets a raise of 9% after hos first year. What os his new salary

viva [34]

Answer:

d + .09d

Step-by-step explanation:

9% of his salary can be found by multiplying d by 0.09. Then simply add that to his original salary to get you answer.

6 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Find the area of the figure

pentagon [3]

For the square area we have:
12.12=144
and for the rectangle we have:
4.11=44

3 0

1 year ago

Find the measure of x.

Andru [333]

Answer:

Step-by-step explanation:

Since the triangles are congruent then corresponding angles are congruent

x is the angle between line with 3 strokes and 2 strokes

The corresponding angle is therefore ∠ C

∠ C = 180° - (63 + 29)° = 180° - 92° = 88°

Then x = 88 → C

5 0

3 years ago

Pls Help! Very Easy! 10 points! Brainliest if you are correct!

SSSSS [86.1K]

We can see that the 33 degrees corresponds to angle A (parallel lines) meaning they’re equal.
This means that 33 + 2x = 5x (5x is the exterior angle, so the other two interior angles’ sum must equal to it)
3x = 33
x = 11

3 0

3 years ago