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3 years ago

if there are 170 students in 12th grade, what percentage of the twelfth grade students have more than one college in mind

1 answer:

5 0

The answer is 31 because the ones that have two colleges is 27 and the ones that have three colleges or more is 23. And if there is 170students you would add the 23+27=53 and divide that by 170.
53/170=31

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You have two job offers. Conn’s offers a weekly salary of $500 plus commission of 3% of sales. Best Buy offers a weekly salary o

denis23 [38]

Answer: y=3x+500 and y=2x+400

Step-by-step explanation:

you are going to get the weekly salary anyways, but the percentage of sales all depends on what you are doing to make sure you are selling things.

7 0

2 years ago

The big dog weighs 5 times as much as the little dog. The little dog weighs 2 3 as much as the medium-sized dog. The medium-size

disa [49]

Answer:

The answer to your question is the big dog weighs 120 pounds

Step-by-step explanation:

Data

big dog = b

medium dog = m

small dog = s

Equations

b = 5s

m = 12 + s

s = 2/3 m

Process

1.- Substitute m in the last equation

s = 2/3(12 + s)

s = 24/3 + 2/3s

s - 2/3s = 8

1/3 s = 8

s = 8(3)

s = 24 pounds

2.- Substitute s in the first equation

b = 5(24)

b = 120 pounds

4 0

3 years ago

Cx=r/d<img src="https://tex.z-dn.net/?f=%5Cfrac%7Br%7D%7Bd%7D" id="TexFormula1" title="\frac{r}{d}" alt="\frac{r}{d}" align="abs

antoniya [11.8K]

Answer:

$x=\frac{rc}{d}$

Step-by-step explanation:

ill take the equation as this

$cx=\frac{r}{d}$

divide both side by c

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}$

Next time when you see someone greif your question, please report it.

Shame for the other guy

Hoped this helped you

Red

8 0

3 years ago

Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen

boyakko [2]

PART A
s = the number of packets of strawberry wafers ;
c = the number of packets of chocolate wafers ;
3 × s + 1 × c = 30 ;
s + c = 22 ;

PART B

The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.

c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;

4 0

3 years ago

Please please help me

zhannawk [14.2K]

We can’t help u if their is no instructions on what u need to do sorry

6 0

3 years ago