Question

A bag contains 5 yellows tickets numbered 1 through 5. The bag also contains 5 green tickets numbers 1 to five. You randomly pick a ticket. It is green or has a number greater than 4. Find the probability of tbhs occuring

Answer 1

Answer:

$\frac{3}{5}$ or 0.6

Step-by-step explanation:

Given:

Number of yellow tickets = 5

Number of green tickets = 5

Total number of tickets = 5 + 5 = 10

Required:

Find the probability that a randomly picked ticket is green or has a number greater than 4

Use the formula:

P = probability of green tickets + probability of yellow tickets with numbers greater than 4

Yellow tickets with numbers greater than 4 = 1 ticket

Probability of picking a green ticket = $\frac{5}{10} = \frac{1}{2}$

Probability of picking a yellow ticket with number greater than 4 = $\frac{1}{10}$

Therefore, probability that a randomly picked ticket is green or has a number greater than 4

= $\frac{1}{2} + \frac{1}{10} = \frac{6}{10}$

$= \frac{3}{5}$

Probability that a randomly picked ticket is green or has a number greater than 4 = $\frac{3}{5}$ or 0.6