At a certain school, the mark out of 100 for Term 1 exam and twice the mark out of 100 for the term 3 exam are added together. T
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The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.
<h3>Can this atrium be built in the rectangular plot of land?</h3>
The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.
First, we calculate the volume occupied by the maximum allowable radius:
<em>V' =</em> (8 · π / 3) · (45 ft)³
<em>V' ≈</em> 763407.015 ft³
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.
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Answer:
(y, -x -6)
Step-by-step explanation:
<em>The coordinates of PQRS is not given, however we'll assume the coordinates of PQRS to be (x,y)</em>
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The first transformation: 6 units right
Where b = 6
So, the new coordinates will be
The second transformation: 90° clockwise
So, the new coordinates will be
<em>Hence, the new coordinates of PQRS is (y, -x - 6)</em>