Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
With this information you can write the expression
9.95m + 5 = 7.99m
This demonstrates the cost for each one after m months.
<h2><em>y
2
+
6
y
−
16
=
(
y
+
8
)
(
y
−
2
)
</em></h2><h2 /><h2><em>Explanation:
</em></h2><h2><em>Note that in general:
</em></h2><h2 /><h2><em>(
y
+
a
)
(y
−
b
)
=
y
2
+
(
a
−
b
)
y
−
a
b
</em></h2><h2 /><h2><em>So we want to find a pair of factors a and b of 16 which differ by 6
. </em></h2><h2><em>The pair 8
,
2 works in that 8−
2
=
6 and 8
⋅
2=
16
.
</em></h2><h2 /><h2><em>Hence:
</em></h2><h2><em>
y
2
+
6
y
−
16
=
(
y+
8
)
(
y
−
2
)</em></h2><h2><em>y=2,-8</em></h2>
Answer:
1. 3/5 c
2. 7 c
3. 2/5 b
4. $3.24 c
5. -3.2 b
Step-by-step explanation:
1.
2/5 + 1/5 = 3/5
2.
a negative + a negative = a positive
2+5 = 7
3.
terminating means the decimal ends. When u divide a & c they keep on going but 2/5 ends
4.
divide 16.8 by 5.19 = 3.23 round up so 3.24
5.
multiply the two together to get the answer
C = 8.5x + 6y
Rearrange the equation by making the side with x, be on the Left Hand Side (LHS)
8.5x + 6y = C
Subtract 6y from both sides of the equation
8.5x + 6y - 6y = C - 6y
8.5x = C - 6y
Divide both sides of the equation by 8.5
(8.5x/8.5) = (C - 6y)/8.5
x = (C - 6y)/8.5
I hope this helped.
