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love history [14]
3 years ago
13

Suppose that the probability that a child living in an urban area in the United States is obese is 20%. If a social worker sees

15 children living in urban areas, answer the following: What is the probability that none are obese
Mathematics
1 answer:
Levart [38]3 years ago
7 0

Answer:

The probability the event that none of them are obese is 0.0352.

Step-by-step explanation:

<h3>Binomial distribution:</h3>

A discrete random variable X having to the set {0,1,2,3....,n} as the spectrum, is said to have binomial distribution with parameters n= the number of trial, and p= probability of successes on an individual trial , if the p.m.f of X is given by,

P(X=x)=\left(\begin{array}{c}n\\x\end{array}\right) p^x(1-p)^{n-x} for x=0,1,2,...,n

                =0                               elsewhere.

where 0<p<1 and  n an positive integer,

Given that,

The probability of the event that a child living in an urban area in the united state is obese is 20%.

n=Number of children = 15, p= 20%= 0.20.

The probability the event that none of them are obese is

=P(X=0)

=\left(\begin{array}{c}15\\0\end{array}\right) (0.20)^0(1-0.20)^{15-0}

=0.0352

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