Answer:
4n - 3
Step-by-step explanation:
Answer:
1595 ft^2
Step-by-step explanation:
The answer is obtained by adding the areas of sectors of several circles.
1. Think of the rope being vertical going up from the corner where it is tied. It goes up along the 10-ft side. Now think of the length of the rope being a radius of a circle, rotate it counterclockwise until it is horizontal and is on top of the bottom 20-ft side. That area is 3/4 of a circle of radius 24.5 ft.
2. With the rope in this position, along the bottom 20-ft side, 4.5 ft of the rope stick out the right side of the barn. That amount if rope allows for a 1/4 circle of 4.5-ft radius on the right side of the barn.
3. With the rope in the position of 1. above, vertical and along the 10-ft left side, 14.5 ft of rope extend past the barn's 10-ft left wall. That extra 14.5 ft of rope are now the radius of a 1/4 circle along the upper 20-ft wall.
The area is the sum of the areas described above in numbers 1., 2., and 3.
total area = area 1 + area 2 + area 3
area of circle = (pi)r^2
total area = 3/4 * (pi)(24.5 ft)^2 + 1/4 * (pi)(4.5 ft)^2 + 1/4 * (pi)(14.5 ft)^2
total area = 1414.31 ft^2 + 15.90 ft^2 + 165.13 ft^2
total area = 1595.34 ft^2
To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.
The work done on moving the object is 27ft*lbs
<h3>Work done in moving the object from point A to point B</h3>
To find the work done on this object, let's find the net force on the object.
Data;
- force = 4lb
- direction = 4, -2
- displacement = 7ft
- direction = (0, 4) to (5,1)
The unit vector of the force is
The net force acting on the object is
The displacement on the object is 7ft through (0,4) to (5, -1)
The unit vector on displacement is
The net displacement will be
The work done will be F.d
The work done on moving the object is 27ft*lbs
Learn more on work done on an object here;
brainly.com/question/26152883
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Step-by-step explanation:
U2 = 7
U1 = 35/2
r = 7 ÷ 35/2
r = 7 × 2/35
r = 14/35
r = 2/5
