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disa [49]
3 years ago
13

Each square on the grid represents 1 m2. What is the approximate area of this grassy field?

Mathematics
2 answers:
Mama L [17]3 years ago
8 0
Fam,

Take the average boundary of it.  So it would be 8 * 4 = 32.

Thus, it must be less than 32 and most likely greater than 20 so its B!
Vladimir [108]3 years ago
6 0
Your answer is B) because all you need to do is count the squares.

Glad I could help, and good luck!
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HELP PLEASE, THANK YOU!
11Alexandr11 [23.1K]
A) f(x) = x-2 because the points in the y axis are -2 from the origin and x goes first
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a swimmer swam 48 kilometers in d days. What is the value of the d if the swimmer swam an average of 3.2 kilometers daily?
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Time= distance/speed

=48/3.2= 15
6 0
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Mrs. Jacobs buys 20 kilograms if rice at $0.84 per kilogram. she buys 700 grams of shrimp at $1.02 per 100 grams.
rusak2 [61]
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700/100=7
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8 0
3 years ago
What are the x-intercepts of the quadratic function? <br> f(x) = x2-3x-10
zzz [600]
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3 0
3 years ago
A population of butterflies grows in such a way that each generation is simply 1.5 times the previous generation. There were 350
kap26 [50]

Answer:

378.5 or just 378

Step-by-step explanation:

This is a linear model with x representing the number of generations that's gone by, y is the number of butterflies after x number of generations has gone by, and the 350 represents the number of butterflies initially (before any time has gone by.  When x = 0, y = 350 so that's the y-intercept of our equation.)

The form for a linear equation is y = mx + b, where m is the rate of change and b is the y-intercept, the initial amount when x = 0.

Our rate of change is 1.5 and the initial amount of butterflies is 350, so filling in the equation we get a model of y = 1.5x + 350.

If we want y when x = 19, plug 19 in for x and solve for y:

y = 1.5(19) + 350

y = 378.5

Since we can't have .5 of a butterfly we will round down to 378

7 0
4 years ago
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