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ASHA 777 [7]
4 years ago
8

Is 1-6 correct please help I will give thanks or brainliest

Mathematics
2 answers:
denpristay [2]4 years ago
6 0
Yes very good you are awesome but just to be confident about yourself check again<span />
PolarNik [594]4 years ago
3 0
Yes, these are correct. Some of them you could simplify if you wanted to though. Hope this helps!
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Chiara pays $21 for 3 DVDs that she finds in a one-price bin. Gunther wants to know how much he would spend for 1 DVD in this bi
balu736 [363]

Answer:

aswer choices please and thank you I guess

6 0
3 years ago
What is pi ? <br><br><br><br><br><br><br> ps. just trying this -.-
marysya [2.9K]
'Pi' ( π ) is the ratio of the circumference of a circle to its diameter.

The exact value of 'pi' can't be completely written with numbers, so whenever
we use 'pi', we always use an approximation.
7 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP! The difference between two-thirds of a number and 4 is -92.
sleet_krkn [62]

Answer:

Step-by-step explanation:

2/3 x - 4 = - 92

add 4 to both sides

2/3 x = - 88

multiply both sides by 3

2 x = - 264

divide both sides by 2

this is ur answer

Good luck

Hope this helps!

5 0
3 years ago
Read 2 more answers
Find a particular solution to the nonhomogeneous differential equation y'' + 4 y = cos(2x) + sin(2x).
alukav5142 [94]
The characteristic solution follows from solving the characteristic equation,

r^2+4=0\implies r=\pm2i

so that

y_c=C_1\cos2x+C_2\sin2x

A guess for the particular solution may be a\cos2x+b\sin2x, but this is already contained within the characteristic solution. We require a set of linearly independent solutions, so we can look to

y_p=ax\cos2x+bx\sin2x

which has second derivative

{y_p}''=(-4ax+4b)\cos2x+(-4bx-4a)\sin2x

Substituting into the ODE, you have

y''+4y=\cos2x+\sin2x
\implies4b\cos2x-4a\sin2x=\cos2x+\sin2x
\implies\begin{cases}4b=1\\-4a=1\end{cases}\implies a=-\dfrac14,b=\dfrac14

Therefore the particular solution is

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

Note that you could have made a more precise guess of

y_p=(a_1x+a_0)\cos2x+(b_1x+b_0)\sin2x

but, of course, any solution of the form a_0\cos2x+b_0\sin2x is already accounted for within y_c.
6 0
3 years ago
Find the inverse of the function.
Akimi4 [234]

Answer:

Step-by-step explanation:

The inverse is found by interchanging the x and y values and solve the result for y.

I will use y for f(x)

y = 4x^2

Inverse

x = 4y^2              Divide by 4

x/4 = 4y^2 /4    

x/4 = y^2             Take the square root of both sides.

sqrt(x/4) = sqrt(y^2)

y = sqrt(x/4)

g(x) = sqrt(x/4)  If you have a very fussy teacher, the inverse function could be written as

g(x) = +/- sqrt(x)/2

I expect that if the question is computer marked, I would try g(x) = sqrt(x)/2 first.

3 0
3 years ago
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