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Aliun [14]
3 years ago
9

What is pi ? ps. just trying this -.-

Mathematics
2 answers:
marysya [2.9K]3 years ago
7 0
'Pi' ( π ) is the ratio of the circumference of a circle to its diameter.

The exact value of 'pi' can't be completely written with numbers, so whenever
we use 'pi', we always use an approximation.
bearhunter [10]3 years ago
7 0
Pi is 3.14, but it also has a symbol,but the symbol is not on my phone, sorry. The symbol also just stands for that number, 3.14. Hope this helps! :)
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Complete the tables to determine if the expressions are equivalent. If the expressions are equivalent, name the properties that
jok3333 [9.3K]
I don’t know how to necessarily complete the tables but i know they are equivalent

1. 3(x-5)
3 (x) = 3x
3 (-5) = -15

that is the distributive property thus it equals

3x - 15

2. 3x - 15

they’re the same

5 0
2 years ago
WILL MARK BRAINLIEST !!!
iren2701 [21]

Answer:

(-3,3) Hope that this does help!

6 0
3 years ago
Which expression is equivalent
almond37 [142]

Answer:10 {x}^{2}  - 4y + 2 {x}^{2}  - y

5 0
3 years ago
Read 2 more answers
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
Maria has $5.00 more than José. Together they have. $37.50.
Soloha48 [4]

Answer:

Step-by-step explanation:

32.50 dollar

8 0
3 years ago
Read 2 more answers
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