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3 years ago

Help me plz 8th grade math need answers quick

Mathematics

1 answer:

mixer [17]3 years ago

8 0

Answer:

25. Not a solution

26. Yes a solution

27. y= 2/3 x

28. y=3x+16

Step-by-step explanation:

25. The solution to a linear equation is the point (x,y). To find if an (x,y) is a solution, substitute it into the equation and see if it works.

y=4x-4 and (8,3)

3=4(8)-4

3=32-4

3=28

False

Not a solution.

26. Repeat 25 to solve 26 with y=5x-5 and (0,-5)

y=5x-5 and (0,-5)

-5=5(0)-5

-5=0-5

-5=-5

True

Yes a solution.

27. This line crosses through the origin is proportional and therefore has the form y=mx. It also has a gentle slant meaning that is less than 1/2 and goes in a positive direction. This means it is y=2/3 x.

28. Use inverse operations to rearrange the equation.

y-3x=16

y=16+3x

y=3x+16

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What is the factored form of -1/2(32x - 40) - (20x - 4)?

inna [77]

Answer:

12(-3x + 2)

Step-by-step explanation:

-1/2 ( 32x - 40) - (20x - 4) = -16x + 20 - 20x + 4 = -36x + 24 = 6(-6x + 4) = 12(-3x + 2)

8 0

3 years ago

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What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

3 years ago

Raj used 4 3/4 cups of sugar for each batch of muffins. He made 3 1/2 batches. Raj used 16 5/8 cups of sugar altogether.

saul85 [17]

Answer:

It is true!

Step-by-step explanation:

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3 years ago

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Hey guys my last question please answer :) peace and love guys

Vadim26 [7]

Looking at the problem statement, this question states for us to determine the range of the function that is provided in a graph is. Let us first determine what range is.

Range ⇒ Range is what y-values can be used in the function that is graphed. For example, if a line just goes up and down all the way to negative and positive infinity, then the range would be negative infinity to positive infinity as it includes all of the y-values in it's solutions.

Now moving back to our problem, we can see that we have a vertex at (2, -5) and that the lowest y-values is at y = -5. Therefore the y-values would be anything greater than or equal to -5 and less than infinity because the lines go forever up in the positive-y-direction.

Therefore, the option that would best match the description that we provided would be option B, -5 ≤ y < ∞.

5 0

2 years ago

Norman buys two cakes. One cake cost 40 cents and the other costs a quarter. How much does he spend in total?

Ivan

Answer: 50 cents

Step-by-step explanation:

Norman buys two cakes. One cake cost 40 cents and the other costs a quarter. Based on this, the cost of the second cake will be:

= 1/4 × 40

= 10 cent

Now, the total amount spent in total will be:

= 40 cents + 10 cents

= 50 cents

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3 years ago