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IceJOKER [234]
3 years ago
8

Help me plz 8th grade math need answers quick

Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

25. Not a solution

26. Yes a solution

27. y= 2/3 x

28. y=3x+16

Step-by-step explanation:

25. The solution to a linear equation is the point (x,y). To find if an (x,y) is a solution, substitute it into the equation and see if it works.

y=4x-4 and (8,3)

3=4(8)-4

3=32-4

3=28

False

Not a solution.

26. Repeat 25 to solve 26 with y=5x-5 and (0,-5)

y=5x-5 and (0,-5)

-5=5(0)-5

-5=0-5

-5=-5

True

Yes a solution.

27. This line crosses through the origin is proportional and therefore has the form y=mx. It also has a gentle slant meaning that is less than 1/2 and goes in a positive direction. This means it is y=2/3 x.

28. Use inverse operations to rearrange the equation.

y-3x=16

y=16+3x

y=3x+16

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5 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
3 years ago
Solve 3|x+2|&lt;12.<br><br> Graph the solutions on the number line.
VikaD [51]

Answer:

-6<x<2

Step-by-step explanation:

5 0
2 years ago
X^2 -9 divided by x+3
WINSTONCH [101]

Step-by-step explanation:

Hey, there!!

Given that,

\frac{ {x}^{2} - 9 }{x + 3}

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

\frac{ {x}^{2} -  {3}^{2}  }{x + 3}

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

\frac{(x + 3)(x - 3)}{(x + 3)}

(x+3) in numerator and denominator gets cancelled,

(x - 3)

Therefore, (x-3) is the final value.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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