A particle P, starting from rest at A, moves in a straight line ABCD. It accelerates uniformly at 5ms-2 from A to B. From B to C
1 answer:
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Answer:
a. The slope of a line parallel to the given line is 1
b. A point on the line parallel to the given line, passing through (−4, 2), is (1,7)
c. The slope of the line perpendicular to the given line is -1
d. A point on the line perpendicular to the given line, passing through (−4, 2), is (3,-5)
Step-by-step explanation:
The equation of the line in Slope-intercept form is:
Where m is the slope and b is the y-intercept.
a. For the line
You can identify that:
By definition, two lines are parallel if they have the same slope. Then, the slope of a line parallel to the given line is:
b. The equation of the line in Point-slope form is:
Where m is the slope and () is a point of the line.
Given the point (-4,2), substitute this point and the slope of the line into the equation:
Give a value to "x", substitute it into this equation and solve for "y":
For :
Then, you get the point (1,7)
c. The slopes of perpendicular lines are negative reciprocals, then the slope of a line perpendicular to the given line is:
d. Given the point (-4,2), substitute this point and the slope of the line into the equation:
Give a value to "x", substitute it into this equation and solve for "y":
For :
Then, you get the point (3,-5)
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
No singular point due to the exponent in the solution
The interval is
b
NONE
Step-by-step explanation:
From the question we are told that
The generally solution is mathematically represented as
=>
integrating both sides
=>
=>
=>
Here
=>
From the above equation we see that the domain for x has no singular point the interval is
Also there is no transient term in the general solution obtained because as there no case where
