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Elza [17]
3 years ago
9

How do you find the slope of a line on a graph

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0
Rise over run
find the difference between two points
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The LCM of two numbers in 2310 and their HCF.
ruslelena [56]

Answer:

The other number is 330

Step-by-step explanation:

The computation of the other number is shown below:

As we know that

HCF × LCM = Product of Two Numbers

So,

30 × 2310 = 210 × other number

Now

The other number is

= (30 ×  2310) ÷ 210

= 330

hence, the other number is 330 and the same is to be considered

We simply applied the above formula so that the correct answer could come

6 0
3 years ago
Guests at an amusement park must be at least 54 inches tall to be able to ride the roller coaster. Which graph represents the se
Gre4nikov [31]

Given:

Guests at an amusement park must be at least 54 inches tall to be able to ride the roller coaster.

To find:

The graph that represents the set of heights that satisfy this requirement.

Solution:

Let x be the height required for the ride.

Guests must be at least 54 inches tall to be able to ride the roller coaster. It means required height is greater than or equal to 54.

x\geq 54

So, 54 and all values above 54 are in the solution set.

Since, 54 is included in the solution set, therefore there is a closed circle at 54. All values above 54 are in the solution set, so everything to the right of the circle is shaded.

Therefore, the correct option is C.

3 0
3 years ago
Read 2 more answers
Factor completely <br> 4(x+1)^2/3 + 12(x+1)^-1/3
wolverine [178]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad&#10;\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\&#10;\left.\qquad \qquad \right.\textit{negative exponents}\\\\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}&#10;\qquad \qquad&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\qquad \qquad &#10;a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}&#10;\\\\&#10;-------------------------------\\\\&#10;%4(x+1)^2/3 + 12(x+1)^-1/3&#10;4(x+1)^{\frac{2}{3}}+12(x+1)^{-\frac{1}{3}}\implies 4(x+1)^{\frac{2}{3}}+12\cfrac{1}{(x+1)^{\frac{1}{3}}}&#10;\\\\\\

\bf 4(x+1)^{\frac{2}{3}}+\cfrac{12}{(x+1)^{\frac{1}{3}}}\impliedby \textit{so, our LCD is }(x+1)^{\frac{1}{3}}&#10;\\\\\\&#10;\cfrac{4(x+1)^{\frac{2}{3}}\cdot (x+1)^{\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)^{\frac{2}{3}+\frac{1}{3}}+12}{(x+1)^{\frac{1}{3}}}&#10;\\\\\\&#10;\cfrac{4(x+1)^{\frac{3}{3}}+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+1)+12}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4x+4+12}{(x+1)^{\frac{1}{3}}}&#10;\\\\\\&#10;\cfrac{4x+16}{(x+1)^{\frac{1}{3}}}\implies \cfrac{4(x+4)}{\sqrt[3]{x+1}}
3 0
4 years ago
Read 2 more answers
Answer quick for brainliest!
Gnom [1K]

A

Step-by-step explanation:

8 0
4 years ago
I need help on this
koban [17]

Answer:

TUS

2. 42 + 62= 104

then ,

180-104= 76

4 0
3 years ago
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